ADA4530-1ARZ-R7 datasheet(32/51 Pages) AD

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Data Sheet

ADA4530-1

Rev. A | Page 31 of 50

Figure 102 shows the phase margin of the ADA4530-1 with

different values of output isolating resistors and capacitive

loads. Figure 103 shows the frequency response with 1 nF

capacitive load and different isolating resistors.

VSY = 10V

AV = +1

RISO = 301Ω

RISO = 499Ω

RISO = 732Ω

100

1000

10000

CAPACITIVE LOAD (pF)

Figure 102. Phase Margin vs. Load Capacitance with Various Output

Isolating Resistors

100

–20

–40

100

–20

–40

VSY = 10V

AV = +1

CL = 1nF

PHASE

GAIN

100k

10k

10M

FREQUENCY (Hz)

GAIN (RISO = 0Ω)

GAIN (RISO = 301Ω)

GAIN (RISO = 732Ω)

PHASE (RISO = 0Ω)

PHASE (RISO = 301Ω)

PHASE (RISO = 732Ω)

Figure 103. Frequency Response with CL = 1 nF and Various Isolating

Resistors

EMI REJECTION RATIO

Circuit performance is often adversely affected by high frequency

electromagnetic interference (EMI). When the signal strength is

low and transmission lines are long, an op amp must accurately

amplify the input signals. However, all op amp pins—the

noninverting input, inverting input, positive supply, negative

supply, and output pins—are susceptible to EMI signals. These high

frequency signals are coupled into an op amp by various means,

such as conduction, near field radiation, or far field radiation. For

example, wires and PCB traces can act as antennas and pick up

high frequency EMI signals.

Amplifiers do not amplify EMI or RF signals due to their

relatively low bandwidth. However, due to the nonlinearities of

the input devices, op amps can rectify these out of band signals.

When these high frequency signals are rectified, they appear as

a dc offset at the output.

To describe the ability of the ADA4530-1 to perform as intended

in the presence of electromagnetic energy, the electromagnetic

interference rejection ratio (EMIRR) of the noninverting pin is

specified in Table 1, Table 2, and Table 3 of the Specifications

section. A mathematical method of measuring EMIRR is

defined as follows:

EMIRR = 20log(VIN_PEAK/ΔVOS)

Figure 104 shows the typical EMIRR vs. frequency performance

for each of the specified supply voltages.

120

100

110

10M

100M

10G

FREQUENCY (Hz)

VSY = 4.5V

VSY = 10V

VSY = 16V

VSY = 4.5V TO 16V

Figure 104. EMIRR vs. Frequency

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