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ST1S50 数据表(PDF) 13 Page - STMicroelectronics

部件名 ST1S50
功能描述  Solid state disk drive, Blu-ray, DVD
PDF  29 Pages
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制造商  STMICROELECTRONICS [STMicroelectronics]
网页  http://www.st.com
标志 STMICROELECTRONICS - STMicroelectronics

ST1S50 数据表(HTML) 13 Page - STMicroelectronics

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ST1S50
Functional description
29
So closing the loop, the loop gain GLOOP(s) is:
Equation 12
To stabilize the loop and then to have the proper phase margin (> 45°) with the requested
bandwidth, RC and CC can be selected as described in Section 6.4 on page 18.
5.3
Overcurrent protection
The ST1S50 device implements the pulse-by-pulse overcurrent protection. The peak
current is sensed through the high-side power MOSFET and when it exceeds the
overcurrent threshold the high-side is immediately turned off and the low-side conducts the
inductor current for the rest of the clock period.
During overload condition, since the duty cycle is not set by the control loop but it is limited
by the overcurrent threshold, the output voltage drops out of regulation. If the FB falls below
0.734 V the switching frequency is divided by two to keep the inductor current limited around
the ILIM value.
The overload condition is allowed for 256 continuous clock cycles. In case the overload
condition persists for longer than 257 clock cycles, the HICCUP protection is triggered: the
device realizes a soft-start cycle and then, if the overcurrent protection is still triggered,
stops switching activities and remains disabled for the HICCUP times. Then it restarts with
a soft-start cycle.
Figure 6. Hiccup behavior with persistent short-circuit
The HICCUP time depends on the selected value of the soft-start capacitor, considering RSS
= 4.7 Mfixed value (see Section 6.5 on page 19).
Equation 13
If the feedback falls below 0.3 V before the 256 clock cycle, as a symptom of a short-circuit,
the HICCUP protection is triggered and the converter reacts as described above in this
section.
GLOOP s

GCO s
 G
DIV s
 G
EA s


=
Soft-start duration
Hiccup duration
THICCUP s

CSS F
 2853934
=



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