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CS48520 数据表(PDF) 10 Page - Cirrus Logic

部件名 CS48520
功能描述  Cost-effective, High-performance 32-bit DSP
PDF  23 Pages
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制造商  CIRRUS [Cirrus Logic]
网页  http://www.cirrus.com
标志 CIRRUS - Cirrus Logic

CS48520 数据表(HTML) 10 Page - Cirrus Logic

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10
DS734F5
5.4 Power Supply Characteristics
5.4 Power Supply Characteristics
(Measurements performed under operating conditions)
5.5 Thermal Data (48-pin LQFP)
Parameter
Symbol
Min
Typ
Max
Unit
High-level input voltage
VIH
2.0
—
—
V
Low-level input voltage, except XTI
VIL
——
0.8
V
Low-level input voltage, XTI
VILXTI
——
0.6
V
Input hysteresis
Vhys
—0.4
—
V
High-level output voltage (IO = –2 mA), except XTI
VOH
VDDIO*0.9
—
—
V
Low-level output voltage (IO = 2 mA), except XTI
VOL
——
VDDIO*0.1
V
Input leakage XTI
ILXTI
——
5
µA
Input leakage current (all digital pins with internal pull-up resistors enabled)
ILEAK
——
70
µA
Parameter
Min
Typ
Max
Unit
Operational Power Supply Current:
VDD: Core and I/O operating1
1.Dependent on application firmware and DSP clock speed.
—
203
—
mA
VDDA: PLL operating
—8
—
mA
VDDIO: With most ports operating
—27
—
mA
Total Operational Power Dissipation:
—
480
—
mW
Standby Power Supply Current:
VDD: Core and I/O not clocked
—
100
—
µA
VDDA: PLL halted
—1
—
µA
VDDIO: All connected I/O pins 3-stated by other ICs in system
—
50
—
µA
Total Standby Power Dissipation
—
348
—
µW
Parameter
Symbol
Min
Typ
Max
Unit
Junction Temperature
Tj
——
125
°C
Thermal Resistance (Junction to Ambient)
Two-layer board1
Four-layer board2
1.Two-layer board is specified as a 76 mm X 114 mm, 1.6 mm thick FR-4 material with 1 oz. copper covering 20% of the top and bottom layers.
2.Four-layer board is specified as a 76 mm X 114 mm, 1.6 mm thick FR-4 material with 1 oz. copper covering 20% of the top and bottom layers and 0.5
oz. copper covering 90 % of the internal power plane and ground plane layers.
θ
ja
—
63.5
—
°C/Watt
—54
—
Thermal Resistance (Junction to Top of Package)
Two-layer board3
Four-layer board4
3.To calculate the die temperature for a given power dissipation
T
j = Ambient Temperature + [(Power Dissipation in Watts)*
θ
ja]
4.To calculate the case temperature for a given power dissipation
T
c = Tj – [(Power Dissipation in Watts)*
ψ
jt]
ψ
jt
—
0.70
—
°C/Watt
—0.64
—



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