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AD8510ARM-R2 数据表(PDF) 15 Page - Analog Devices |
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AD8510ARM-R2 数据表(HTML) 15 Page - Analog Devices |
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15 / 20 page ![]() AD8510/AD8512/AD8513 Rev. H | Page 15 of 20 Figure 46 shows a scope plot of the output of the AD8510/AD8512/ AD8513 in response to a 400 mV pulse. The circuit is configured in positive unity gain (worst case) with a load experience of 500 pF. TIME (1µs/DIV) VSY = ±15V CL = 500pF RL =10kΩ Figure 46. Capacitive Load Drive Without Snubber When the snubber circuit is used, the overshoot is reduced from 55% to less than 3% with the same load capacitance. Ringing is virtually eliminated, as shown in Figure 47. TIME (1µs/DIV) VSY = ±15V RL = 10kΩ CL = 500pF RS = 100Ω CS = 1nF Figure 47. Capacitive Load with Snubber Network Optimum values for RS and CS depend on the load capacitance and input stray capacitance and are determined empirically. Table 5 shows a few values that can be used as starting points. Table 5. Optimum Values for Capacitive Loads CLOAD RS (Ω) CS 500 pF 100 1 nF 2 nF 70 100 pF 5 nF 60 300 pF OPEN-LOOP GAIN AND PHASE RESPONSE In addition to their impressive low noise, low offset voltage, and offset current, the AD8510/AD8512/AD8513 have excellent loop gain and phase response even when driving large resistive and capacitive loads. Compared with Competitor A (see Figure 49) under the same conditions, with a 2.5 kΩ load at the output, the AD8510/AD8512/ AD8513 have more than 8 MHz of bandwidth and a phase margin of more than 52°. Competitor A, on the other hand, has only 4.5 MHz of band- width and 28° of phase margin under the same test conditions. Even with a 1 nF capacitive load in parallel with the 2 kΩ load at the output, the AD8510/AD8512/AD8513 show much better response than Competitor A, whose phase margin is degraded to less than 0, indicating oscillation. FREQUENCY (Hz) 10k –30 –20 –10 100k 0 10 30 1M 10M 50M 40 50 20 60 70 –135 –90 –45 0 45 90 135 180 225 270 315 VSY = ±15V RL = 2.5kΩ CL = 0pF Figure 48. Frequency Response of the AD8510/AD8512/AD8513 FREQUENCY (Hz) 10k –30 –20 –10 100k 0 10 30 1M 10M 50M 40 50 20 60 70 –135 –90 –45 0 45 90 135 180 225 270 315 VSY = ±15V RL = 2.5kΩ CL = 0pF Figure 49. Frequency Response of Competitor A |
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