AD9518-2ABCPZ datasheet(36/64 Pages) AD

36 / 64 page

AD9518-2

Data Sheet

Rev. C | Page 36 of 64

The duty cycle at the output of the channel divider for various

configurations is shown in Table 33 to Table 35.

Table 33. Duty Cycle with VCO Divider, Input Duty Cycle Is 50%

VCO

Divider

Output Duty Cycle

N + M + 2

DCCOFF = 1

DCCOFF = 0

Even

1 (divider

bypassed)

50%

Odd = 3

1 (divider

bypassed)

33.3%

50%

Odd = 5

1 (divider

bypassed)

40%

50%

Even, Odd

Even

(N + 1)/

(N + M + 2)

50%; requires M = N

Even, Odd

Odd

(N + 1)/

(N + M + 2)

50%; requires M = N + 1

Table 34. Duty Cycle with VCO Divider, Input Duty Cycle Is X%

VCO

Divider

Output Duty Cycle

N + M + 2

DCCOFF = 1

DCCOFF = 0

Even

1 (divider

bypassed)

50%

Odd = 3

1 (divider

bypassed)

33.3%

(1 + X%)/3

Odd = 5

1 (divider

bypassed)

40%

(2 + X%)/5

Even

(N + 1)/

(N + M + 2)

50%,

requires M = N

Odd

(N + 1)/

(N + M + 2)

50%,

requires M = N + 1

Odd = 3

Even

(N + 1)/

(N + M + 2)

50%,

requires M = N

Odd = 3

Odd

(N + 1)/

(N + M + 2)

(3N + 4 + X%)/(6N + 9),

requires M = N + 1

Odd = 5

Even

(N + 1)/

(N + M + 2)

50%,

requires M = N

Odd = 5

Odd

(N + 1)/

(N + M + 2)

(5N + 7 + X%)/(10N + 15),

requires M = N + 1

Table 35. Channel Divider Output Duty Cycle When the

VCO Divider Is Not Used

Input Clock

Duty Cycle

Output Duty Cycle

N + M + 2

DCCOFF = 1

DCCOFF = 0

Any

1 (divider

bypassed)

Same as input

duty cycle

Any

Even

(N + 1)/

(M + N + 2)

50%, requires M = N

50%

Odd

(N + 1)/

(M + N + 2)

50%, requires

M = N + 1

Odd

(N + 1)/

(M + N + 2)

(N + 1 + X%)/(2 × N + 3),

requires M = N + 1

The internal VCO has a duty cycle of 50%. Therefore, when the

VCO is connected directly to the output, the duty cycle is 50%.

If the CLK input is routed directly to the output, the duty cycle of

the output is the same as the CLK input.

Phase Offset or Coarse Time Delay (0, 1, and 2)

Each channel divider allows for a phase offset, or a coarse time

delay, to be programmed by setting register bits (see Table 36).

These settings determine the number of cycles (successive

rising edges) of the channel divider input frequency by which to

offset, or delay, the rising edge of the output of the divider. This

delay is with respect to a nondelayed output (that is, with a

phase offset of zero). The amount of the delay is set by five bits

loaded into the phase offset (PO) register plus the start high (SH)

bit for each channel divider. When the start high bit is set, the

delay is also affected by the number of low cycles (M) that are

programmed for the divider.

The sync function must be used to make phase offsets effective

(see the Synchronizing the Outputs—Sync Function section).

Table 36. Setting Phase Offset and Division for Divider 0,

Divider 1, and Divider 2

Divider

Start

High (SH)

Phase

Offset (PO)

Low Cycles

High Cycles

0x191[4]

0x191[3:0]

0x190[7:4]

0x190[3:0]

0x194[4]

0x194[3:0]

0x193[7:4]

0x193[3:0]

0x197[4]

0x197[3:0]

0x196[7:4]

0x196[3:0]

Let

Δt = delay (in seconds).

Δc = delay (in cycles of clock signal at input to DX).

TX = period of the clock signal at the input of the divider, DX

(in seconds).

Φ = 16 × SH[4] + 8 × PO[3] + 4 × PO[2] + 2 × PO[1] + 1 × PO[0]

The channel divide-by is set as N = high cycles and M = low cycles.

Case 1

For Φ ≤ 15,

Δt = Φ × TX

Δc = Δt/TX = Φ

Case 2

For Φ ≥ 16,

Δt = (Φ − 16 + M + 1) × TX

Δc = Δt/TX

By giving each divider a different phase offset, output-to-output

delays can be set in increments of the channel divider input

clock cycle. Figure 40 shows the results of setting such a coarse

offset between outputs.

CHANNEL DIVIDER OUTPUTS

DIV = 4, DUTY = 50%

10 11 12 13 14 15

DIVIDER 0

DIVIDER 1

DIVIDER 2

CHANNEL

DIVIDER INPUT

SH = 0

PO = 0

SH = 0

PO = 1

SH = 0

PO = 2

1 × Tx

2 × Tx

Figure 40. Effect of Coarse Phase Offset (or Delay)

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