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LT1336CS 数据表(PDF) 10 Page - Linear Technology |
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LT1336CS 数据表(HTML) 10 Page - Linear Technology |
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10 / 16 page ![]() 10 LT1336 APPLICATIONS INFORMATION In applications where switching is always above 10kHz and the duty cycle never exceeds 90%, Pins 1, 15 and 16 can be left open. The bootstrap capacitor is then charged by conventional bootstrapping. Only a diode needs to be connected between V + and the Boost pin. A 0.1 µF boot- strap capacitor is usually adequate using this technique for driving a single MOSFET under 10,000pF. When driv- ing multiple MOSFETs in parallel, if the total gate capaci- tance exceeds 10,000pF, the bootstrap capacitor should be increased proportionally above 0.1 µF (see Paralleling MOSFETs). Deriving the Floating Supply with the Boost Topology The advantage of using the boost topology is its simplicity. Only a resistor, a small inductor, a diode and a capacitor are needed. However, the high voltage rail may not exceed 40V to avoid reaching the collector-base breakdown volt- age of the internal NPN switch. The recommended values for the current sense resistor, inductor and bootstrap capacitor are 2 Ω, 200µH and 1µF respectively. Using the recommended component values the boost regulator will run at around 700kHz. To lower the frequency the inductor value can be increased and to increase the frequency the inductor value can be de- creased. The sense resistor should be at least 1.5 Ω to maintain adequate inductor current limit. The bootstrap capacitor value should be 1 µF or larger to minimize ripple voltage. An example of a boost regulator is shown in Figure 1. Figure 1. Using the Boost Regulator SWITCH SV+ PV+ RSENSE 2 Ω 1/4W CBOOST 1 µF D2 1N4148 S HV = 40V MAX – + VBOOST 1336 F01 LT1336 200 µH* D1 1N4148 * SUMIDA RCR-664D-221KC + + SWGND ISENSE TGATEDR TGATEFB BOOST TSOURCE The boost regulator works as follows: when switch S is on, the inductor current ramps up as the magnetic field builds up. During this interval energy is being stored in the inductor and no power is transferred to VBOOST. When the inductor peak current is reached, sensed by the 2 Ω resistor, the switch is turned off. Energy is no longer transferred to the inductor causing the magnetic field to collapse. The collapsing magnetic field induces a change in voltage across the inductor. The Switch pin voltage rises until diode D2 starts conducting. As the inductor current ramps down, the lower inductor current threshold is reached and switch S is turned off, thus completing the cycle. Current drawn from V + is delivered to VBOOST. Some of this current (~ 1.5mA) flows through the topside driver to the Top Source pin. This current is typically returned to ground via the bottom MOSFET or the output load. If the bottom MOSFET were off and the output load were re- turned to HV, then the Top Source pin will return the current to HV through the top MOSFET or the output load. If the HV supply cannot sink current and no load drawing greater than 1.5mA is connected to the supply, then a resistor from HV to ground may be needed to prevent voltage buildup on the HV supply. Note that the current drawn from V + and delivered to VBOOST is significantly higher than the current drawn from VBOOST as given by: II V V IN V OUT BOOST + + = Deriving the Floating Supply with the Flyback Topology For applications where the high voltage rail is greater than 40V, the flyback topology must be used. To configure a flyback regulator, a resistor, a diode, a small 1:1 turns ratio transformer and a capacitor are needed. The maximum voltage across the switch, assuming an ideal transformer, will be about V + + 11.3V. Leakage inductance in nonideal transformers will induce an overvoltage spike at the switch at the instant when it opens. These spikes can be clamped using a snubbing network or a Zener. Unlike the boost topology, the current drawn from V + (assuming no loss) is equal to the current drawn from VBOOST. |
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