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ADP5071ACPZ-R7 数据表(PDF) 21 Page - Analog Devices

部件名 ADP5071ACPZ-R7
功能描述  Independent Positive and Negative Outputs
PDF  28 Pages
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制造商  AD [Analog Devices]
网页  http://www.analog.com
标志 AD - Analog Devices

ADP5071ACPZ-R7 数据表(HTML) 21 Page - Analog Devices

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ADP5071
Data Sheet
Rev. A | Page 20 of 27
When the ADP5071 inverting regulator is operated in CCM at
duty cycles greater than 50%, slope compensation is required to
stabilize the current mode loop. For stable current mode operation,
ensure that the selected inductance is equal to or greater than
the minimum calculated inductance, LMIN2, for the application
parameters in the following equation:
×
=
>
16
.
0
)
1
(
13
.
0
2
IN
MIN2
DUTY
V
L
L2
(µH)
Table 11 suggests a series of inductors to use with the ADP5071
inverting regulator.
LOOP COMPENSATION
The ADP5071 uses external components to compensate the
regulator loop, allowing the optimization of the loop dynamics
for a given application. It is recommended to use the ADIsimPower
tool to calculate compensation components.
Boost Regulator
The boost converter produces an undesirable right half plane
zero in the regulation feedback loop. This feedback loop requires
compensating the regulator such that the crossover frequency
occurs well below the frequency of the right half plane zero. The
right half plane zero is determined by the following equation:
L1
DUTY
R
RHP
f
1
LOAD1
Z1
×
=
π
2
)
1
(
)
(
2
where:
fZ1(RHP) is the right half plane zero frequency.
RLOAD1 is the equivalent load resistance or the output voltage
divided by the load current.
+
+
=
DIODE1
POS
DIODE1
IN
POS
1
V
V
V
V
V
DUTY
where VDIODE1 is the forward voltage drop of the Schottky
diode (D1).
To stabilize the regulator, ensure that the regulator crossover
frequency is less than or equal to one-tenth of the right half
plane zero frequency.
The boost regulator loop gain is
OUT1
CS1
COMP1
OUT1
M1
POS
IN
POS
FB1
VL1
Z
G
Z
||
R
G
V
V
V
V
A
×
×
×
×
×
=
where:
AVL1 is the loop gain.
VFB1 is the feedback regulation voltage
VPOS is the regulated positive output voltage.
VIN is the input voltage.
GM1 is the error amplifier transconductance gain.
ROUT1 is the output impedance of the error amplifier and is 33 MΩ.
ZCOMP1 is the impedance of the series RC network from
COMP1 to AGND.
GCS1 is the current sense transconductance gain (the inductor
current divided by the voltage at COMP1), which is internally
set by the ADP5071and is 12.5 A/V.
ZOUT1 is the impedance of the load in parallel with the output
capacitor.
To determine the crossover frequency (fC1), it is important to
note that, at that frequency, the compensation impedance (ZCOMP1)
is dominated by a resistor (RC1), and the output impedance (ZOUT1)
is dominated by the impedance of an output capacitor (COUT1).
Therefore, when solving for the crossover frequency, the equation
(by definition of the crossover frequency) is simplified to
1
2
1
=
×
×
×
×
×
×
×
=
OUT1
C1
CS1
C1
M1
POS
IN
POS
FB1
VL1
C
f
π
G
R
G
V
V
V
V
A
where fC1 is the crossover frequency.
To solve for RC1, use the following equation:
CS1
M1
IN
FB1
POS
OUT1
C1
C1
G
G
V
V
(V
C
f
R
×
×
×
×
×
×
=
2
)
2π
where GCS1 = 12.5 A/V.
Using typical values for VFB1 and GM1 results in
IN
POS
OUT1
C1
C1
V
(V
C
f
R
2
)
2094
×
×
×
=
For better accuracy, it is recommended to use the value of output
capacitance, COUT1, expected for the dc bias conditions under
which it operates under in the calculation for RC1.
After the compensation resistor is known, set the zero formed
by the compensation capacitor and resistor to one-fourth of the
crossover frequency, or
C1
C1
C1
R
f
π
C
×
×
=
2
where CC1 is the compensation capacitor value.
ERROR
AMPLIFIER
REF1
gM1
FB1
COMP1
RC1
CB1
CC1
Figure 45. Compensation Components
The capacitor, CB1, is chosen to cancel the zero introduced by
the output capacitor ESR. Solve for CB1 as follows:
C1
OUT1
B1
R
C
ESR
C
×
=



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