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ADP2325ACPZ-R7 数据表(PDF) 24 Page - Analog Devices

部件名 ADP2325ACPZ-R7
功能描述  Dual 5 A, 20 V Synchronous Step-Down
PDF  32 Pages
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制造商  AD [Analog Devices]
网页  http://www.analog.com
标志 AD - Analog Devices

ADP2325ACPZ-R7 数据表(HTML) 24 Page - Analog Devices

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ADP2325
Data Sheet
Rev. 0 | Page 24 of 32
DESIGN EXAMPLE
This section describes the design procedure and component
selection for the example application shown in Figure 54, and
Table 11 provides a list of the required settings.
Table 11. Dual Step-Down DC-to-DC Regulator Requirements
Parameter
Specification
Channel 1
Input Voltage
VIN1 = 12.0 V ± 10%
Output Voltage
VOUT1 = 1.2 V
Output Current
IOUT1 = 5 A
Output Voltage Ripple
ΔVOUT1_RIPPLE = 12 mV
Load Transient
±5%, 1 A to 4 A, 1 A/µs
Channel 2
Input Voltage
VIN2 = 12.0 V ± 10%
Output Voltage
VOUT2 = 3.3 V
Output Current
IOUT2 = 5 A
Output Voltage Ripple
ΔVOUT2_RIPPLE = 33 mV
Load Transient
±5%, 1 A to 4 A, 1 A/µs
Switching Frequency
fSW = 500 kHz
OUTPUT VOLTAGE SETTING
Choose a 10 kΩ top feedback resistor (RTOP); calculate the
bottom feedback resistor using the following equation:
×
=
6
.
0
6
.
0
OUT
TOP
BOT
V
R
R
To set the output voltage to 1.2 V, the resistor values are RTOP1 =
10 kΩ and RBOT1 = 10 kΩ. To set the output voltage to 3.3 V,
the resistors values are RTOP2 = 10 kΩ and RBOT2 = 2.21 kΩ.
CURRENT-LIMIT SETTING
For 5 A output current operation, the typical peak current
limit is 8 A. In this case, no RILIM is required.
FREQUENCY SETTING
To set the switching frequency to 500 kHz, use the following
equation to calculate the resistor value, ROSC:
( )
(
)
kHz
000
,
60
SW
OSC
f
R
=
Therefore, ROSC =120 kΩ.
INDUCTOR SELECTION
The peak-to-peak inductor ripple current, ΔIL, is set to 30%
of the maximum output current. Use the following equation
to estimate the value of the inductor:
(
)
SW
L
OUT
IN
f
I
D
V
V
L
×
×
=
For VOUT1 = 1.2 V, Inductor L1 = 1.4 µH, and for VOUT2 = 3.3 V,
Inductor L2 = 3.2 µH.
Select the standard inductor value of 1.5 µH and 3.3 µH for
the 1.2 V and 3.3 V rails.
Calculate the peak-to-peak inductor ripple current as follows:
(
)
SW
OUT
IN
L
f
L
D
V
V
I
×
×
=
For VOUT1 = 1.2 V, ΔIL1 = 1.44 A. For VOUT2 = 3.3 V, ΔIL2 = 1.45 A.
Find the peak inductor current using the following equation:
2
L
OUT
PEAK
I
I
I
+
=
For the 1.2 V rail, the peak inductor current is 5.73 A, and for
the 3.3 V rail, the peak inductor current is 5.73 A.
The rms current through the inductor can be estimated by
12
2
2
L
OUT
RMS
I
I
I
+
=
The rms current of the inductor for both the 1.2 V and 3.3 V
rails is approximately 5.02 A.
For the 1.2 V rail, select an inductor with a minimum rms
current rating of 5.01 A and a minimum saturation current
rating of 5.73 A. For the 3.3 V rail, select an inductor with a
minimum rms current rating of 5.02 A and a minimum
saturation current rating of 5.73 A.
Based on these requirements, for the 1.2 V rail, select a
1.5 µH inductor, such as the Sumida CDRH105RNP-1R5N,
with a DCR = 5.8 mΩ; for the 3.3 V rail, select a 3.3 µH
inductor, such as the Sumida CDRH105RNP-3R3N, with a
DCR = 10.4 mΩ.
OUTPUT CAPACITOR SELECTION
The output capacitor is required to meet the output voltage
ripple and load transient requirements. To meet the output
voltage ripple requirement, use the following equation to
calculate the capacitance and ESR:
RIPPLE
OUT
SW
L
OUT_RIPPLE
V
f
I
C
_
8
×
×
=
L
RIPPLE
OUT
ESR
I
V
R
_
=
For VOUT1 = 1.2 V, COUT_RIPPLE1 = 30 µF and RESR1 = 8.3 mΩ. For
VOUT2 = 3.3 V, COUT_RIPPLE2 = 11 µF and RESR2 = 23 mΩ.



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