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MAT02 数据表(PDF) 9 Page - Analog Devices |
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MAT02 数据表(HTML) 9 Page - Analog Devices |
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9 / 12 page ![]() MAT02 –9– REV. E Collector current range is the key design decision. The inher- ently low rBE of the MAT02 allows the use of a relatively high collector current. For input scaling of ±10 V full-scale and using a 10 V reference, we have a collector-current range for I1 and I2 of: –10 10 1010 12 1 2 RR I RR C + ≤≤ + (13) Practical values for R1 and R2 would range from 50 k Ω to 100 k Ω. Choosing an R 1 of 82 k Ω and R 2 of 62 k Ω provides a collector current range of approximately 39 µA to 283 µA. An RO of 108 k Ω will then make the output scale factor 1/10 and VO = VXVY/10. The output, as well as both inputs, are scaled for ±10 V full scale. Linear error for this circuit is substantially improved by the small correction voltage applied to the base of Q1 as shown in Figure 5. Assuming an equal bulk emitter resistance for each MAT02 transistor, then the error is nulled if: (I1 + I2 – I3 – IO) rBE + ρV O = 0 The currents are known from the previous discussion, and the relationship needed is simply: VO = rBE RO VO (14) The output voltage is attenuated by a factor of rBE/RO and ap- plied to the base of Q1 to cancel the summation of voltage drops due to rBEIC terms. This will make In (I1 I2/I3 IO) more nearly zero which will thereby make IO = I1 I2/I3 a more accurate rela- tionship. Linearity of better than 0.1% is readily achievable with this circuit if the MAT02 pairs are carefully kept at the same temperature. Figure 6. Multifunction Converter MULTIFUNCTION CONVERTER The multifunction converter circuit provides an accurate means of squaring, square rooting, and raising ratios to arbitrary pow- ers. The excellent log conformity of the MAT02 allows a wide range of exponents. The general transfer function is: VO = VY V Z V X m (15) VX, VY, and VZ are input voltages and the exponent “m” has a practical range of approximately 0.2 to 5. Inputs VX and VY are often taken from a fixed reference voltage. With a REF01 pro- viding a precision 10 V to both VX and VY, the transfer function would simplify to: VO = 10 V Z 10 m (16) As with the multiplier/divider circuits, assume that the transistor pairs have excellent matching and are at the same temperature. The In ISA/ISB will then be zero. In the circuit of Figure 6, the voltage drops across the base-emitter junctions of Q1 provide: RB RB + KR A V A = kT q In IZ IX (17) IZ is VZ/R1 and IX is VX/R1. Similarly, the relationship for Q2 is: RB RB + 1– K ()R A V A = kT q In IO I Y (18) IO is VO/RO and IY is VY/R1. These equations for Q1 and Q2 can then be combined. RB + KR A RB + 1– K ()R A In IZ IX = In IO IY (19) |
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