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ADE7756 数据表(PDF) 21 Page - Analog Devices |
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ADE7756 数据表(HTML) 21 Page - Analog Devices |
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21 / 32 page ![]() REV. 0 ADE7756 –21– ACTIVE POWER CALCULATION Electrical power is defined as the rate of energy flow from source to load. It is given by the product of the voltage and current wave- forms. The resulting waveform is called the instantaneous power signal and it is equal to the rate of energy flow at every instant of time. The unit of power is the watt or joules/sec. Equation 3 gives an expression for the instantaneous power signal in an ac system. vt V t ( ) sin( ) = 2 ω (1) it I t ( ) sin( ) = 2 ω (2) where V = rms voltage, I = rms current. pt vt i t p t VI VI t () () () ( ) – cos ( ) =× = 2 ω (3) The average power over an integral number of line cycles (n) is given by the expression in Equation 4. P nT p t dt VI nT == ∫ 1 0 () (4) where T is the line cycle period. and P is referred to as the Active or Real Power. Note that the active power is equal to the dc component of the instantaneous power signal p(t) in Equation 3 , i.e., VI. This is the relationship used to calculate active power in the ADE7756. The instantaneous power signal p(t) is generated by multiplying the current and voltage signals. The dc component of the instan- taneous power signal is then extracted by LPF2 (Low-Pass Filter) to obtain the active power information. This process is graphi- cally illustrated in Figure 26. Since LPF2 does not have an ideal “brick wall” frequency response—see Figure 27—the Active Power signal will have some ripple due to the instantaneous power signal. This ripple is sinusoidal and has a frequency equal to twice the line frequency. Since the ripple is sinusoidal in nature it will be removed when the Active Power signal is inte- grated to calculate Energy—see Energy Calculation section. VOLTAGE CURRENT INSTANTANEOUS POWER SIGNAL ACTIVE REAL POWER SIGNAL = V I 00000h 1999Ah V. I. CCCDh p(t) = V 1 – V 1 COS(2 t) I(t) = 2 I SIN( t) V(t) = 2 V SIN( t) Figure 26. Active Power Calculation Figure 28 shows the signal processing chain for the Active Power calculation in the ADE7756. As explained, the Active Power is calculated by low-pass filtering the instantaneous power signal. FREQUENCY – Hz –24 1 –20 3 10 30 100 –12 –16 –8 –4 0 Figure 27. Frequency Response of LPF2 CCCDh 00h HPF 20 20 LPF2 MULTIPLIER INSTANTANEOUS POWER SIGNAL p(t) = –40%FS TO +40%FS ACTIVE POWER SIGNAL – P I V CURRENT SIGNAL – I(t) 1 VOLTAGE SIGNAL – V(t) 1999Ah Figure 28. Active Power Signal Processing Shown in Figure 29 is the maximum code (Hexadecimal) out- put range for the Active Power signal (LPF2). Note that the output range changes, depending on the contents of the Active Power Gain register—see Channel 1 ADC section. The mini- mum output range is given when the Active Power Gain register contents are equal to 800h, and the maximum range is given by writing 7FFh to the Active Power Gain register. This can be used to calibrate the Active Power (or Energy) calculation in the ADE7756. 00000h +20% FS –20% FS +30% FS +10% FS –10% FS –30% FS CCCDh F3333h 000h 7FFh 800h CHANNEL 1 (ACTIVE POWER) CALIBRATION RANGE POSITIVE POWER 6666h F999Ah 1999Ah E6666h APGAIN[11:0] NEGATIVE POWER Figure 29. Active Power Calculation Output Range |
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