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LTC2925IGN 数据表(PDF) 14 Page - Linear Technology

部件名 LTC2925IGN
功能描述  Multiple Power Supply Tracking Controller with Power Good Timeout
PDF  20 Pages
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制造商  LINER [Linear Technology]
网页  http://www.linear.com
标志 LINER - Linear Technology

LTC2925IGN 数据表(HTML) 14 Page - Linear Technology

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LTC2925
14
2925f
Ratiometric Tracking Example
This example converts the coincident tracking example to
the ratiometric tracking profile shown in Figure 13, using
three supplies without an external FET. The ramp rate of
the master signal remains unchanged (Step 1) and there
is no delay in ratiometric tracking (Step 3), so only the
result of step 2 in the 3-step design procedure needs to be
considered. In this example, the ramp rate of the 1.8V
slave 1 supply ramps up at 60V/s, the 2.5V slave 2 supply
ramps up at 85V/s, and the 1.5V slave 3 supply ramps up
at 50V/s. Always verify that the chosen ramp rate will allow
the supplies to ramp-up completely before RAMPBUF
reaches VCC. If the 1.8V supply were to ramp-up at 50V/s
it would only reach 1.65V because the RAMPBUF signal
would reach its final value of VCC = 3.3V before the slave
supply reached 1.8V.
2.
Solve for the pair of resistors that provide the desired
slave supply behavior, assuming no delay.
From Equation 2:
Rk
Vs
Vs
k
TB =•
16 5
100
60
27 4
..
APPLICATIO S I FOR ATIO
Figure 13. Ratiometric Tracking from Figure 14
SLAVE2
SLAVE1
SLAVE3
0.1
µF
CPGTMR
0.82
µF
10k
VCC SENSEP SENSEN
3.3V
VIN
3.3V
RONB
154k
RTB1
27.4k
RTB2
100k
RFA2
41.2k
2.5V
SLAVE2
RFB2
88.7k
RTA2
38.3k
RTB3
174k
RTA3
63.4k
RTA1
10k
RONA
100k
RAMPBUF
TRACK1
TRACK2
TRACK3
FB2
LTC2925
PGTMR
CSDTMR
0.082
µF
SDTMR
CSCTMR
0.41
µF
SCTMR
GND
2925 F14
RFA3
100k
1.5V
SLAVE3
RFB3
86.6k
DC/DC
IN
FB = 0.8V
OUT
DC/DC
IN
FB = 0.8V
RUN/SS
RUN/SS
OUT
FB3
3.3V
PGI
RFA1
35.7k
1.8V
SLAVE1
RFB1
16.5k
SUPPLY
MONITOR
DC/DC
IN
FB = 1.235V
RUN/SS
OUT
FB1
FAULT
ON
10k
VIN
STATUS
REMOTE
RST
CGATE
0.1
µF
3.3V VIN
GATE
RAMP
SD3
SD2
SD1
Figure 14. Ratiometric Tracking Example
10ms/DIV
2925 F13b
10ms/DIV
2925 F13a
1V/DIV
1V/DIV
From Equation 3:
R
V
V
k
V
k
V
k
k
TA ′=
+
08
1 235
16 5
1 235
35 7
08
27 5
10
.
.
.
.
.
.
.
Step 3 is unnecessary because there is no delay, so
RTA = RTA´.



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