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4LS5K 数据表(PDF) 51 Page - OSRAM GmbH

部件名 4LS5K
功能描述  4LS15K, 4LS10K and 4LS5K Line Scan Sensors
PDF  115 Pages
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制造商  OSRAM [OSRAM GmbH]
网页  http://www.osram.com
标志 OSRAM - OSRAM GmbH

4LS5K 数据表(HTML) 51 Page - OSRAM GmbH

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4LS
Functional Description
Datasheet
• PUBLIC
DS000542
• v3-01 • 2022-Nov-17
114
│ 50
8-Bit mode @ 80 MHz
Below described is an example to calculate the maximum line rate for 8-bit mode, for the below
configuration. The region of interested is based on Figure 71.
Output mode: 8-bit
Readout mode: 1-To-1 LVDS
ADC response stabilization OFF
Auto-start AD OFF
Auto-start readout OFF
End of Range = 0x3F
For full resolution, it was verified that the minimum Readout Time is much higher than the ADC time,
therefore the maximum line rate was defined by the Readout Time. When performing a ROI in sensor,
the goal is to calculate how much the Readout Time can be decreased to achieve the highest line rate
possible.
Taking in consideration Equation 4, the MTA and maximum line rate as shown below:
Figure 73:
8-Bit Timing Clocks with ROI On for Readout Mode 1-To-1
– MTA Calculation
Parameters
Clocks
ADC Time
280
SAMPLE
40
START_AD
2
TBTW_START_AD&RST_RAMP
1
TBTW_SAMPLE&START_AD
12
DTI
112
MTA
335 => 238.8 kLines/s
Max Integration Time(1)
223 => 2787.5 ns
(1)
To use the sensor at the maximum line, this is the maximum integration time possible. When it comes to the minimum
integration time, in theory, it is possible to use a lower integration time, but it was not tested on this configuration. From
an application perspective, using a lower integration time, does not bring significant advantages, once the line rate
cannot be higher and the system would need to increase the illumination power.
Now the Readout Time needs to be calculated in order to achieve the respective line rate and
guarantee the minimum LVAL Low Period.
Start Region of Interest Register Segment A = 0x54 = 84d
Start Region of Interest Register Segment B = 0x00
End Region of interest Register Segment A = 0xA0 = 160d
End Region of Interest Register Segment B = 0x4C = 76d
������������������������ = ((160 − 84) + 1) × (4 × 1)) = 308 ������������������������������������
������������������������������������������ ������������������������ = 308 + 26 = 334 ������������������������������������



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