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VS1103B 数据表(PDF) 48 Page - List of Unclassifed Manufacturers

部件名 VS1103B
功能描述  MIDI/ADPCM AUDIO CODEC
PDF  61 Pages
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制造商  ETC2 [List of Unclassifed Manufacturers]
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标志 ETC2 - List of Unclassifed Manufacturers

VS1103B 数据表(HTML) 48 Page - List of Unclassifed Manufacturers

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VLSI
Solution
y
VS1103b
VS1103B
8. VS1103B REGISTERS
8.8 Interrupt Registers
Interrupt registers, prefix INT
Reg
Type
Reset
Abbrev[bits]
Description
0xC01A
rw
0
ENABLE[7:0]
Interrupt enable.
0xC01B
w
0
GLOB DIS[-]
Write to add to interrupt counter.
0xC01C
w
0
GLOB ENA[-]
Write to subtract from interript counter.
0xC01D
rw
0
COUNTER[4:0]
Interrupt counter.
INT ENABLE controls the interrupts. The control bits are as follows:
INT ENABLE bits
Name
Bits
Description
INT EN TIM1
7
Enable Timer 1 interrupt.
INT EN TIM0
6
Enable Timer 0 interrupt.
INT EN RX
5
Enable UART RX interrupt.
INT EN TX
4
Enable UART TX interrupt.
INT EN MODU
3
Enable AD modulator interrupt.
INT EN SDI
2
Enable Data interrupt.
INT EN SCI
1
Enable SCI interrupt.
INT EN DAC
0
Enable DAC interrupt.
Note: It may take upto 6 clock cycles before changing INT ENABLE has any effect.
Writing any value to INT GLOB DIS adds one to the interrupt counter INT COUNTER and effectively
disables all interrupts. It may take upto 6 clock cycles before writing to this register has any effect.
Writing any value to INT GLOB ENA subtracts one from the interrupt counter (unless INT COUNTER
already was 0). If the interrupt counter becomes zero, interrupts selected with INT ENABLE are re-
stored. An interrupt routine should always write to this register as the last thing it does, because in-
terrupts automatically add one to the interrupt counter, but subtracting it back to its initial value is the
responsibility of the user. It may take upto 6 clock cycles before writing this register has any effect.
By reading INT COUNTER the user may check if the interrupt counter is correct or not. If the register
is not 0, interrupts are disabled.
Version 1.01, 2007-09-03
48



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