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ADE7166 数据表(PDF) 64 Page - Analog Devices |
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ADE7166 数据表(HTML) 64 Page - Analog Devices |
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64 / 148 page ![]() ADE75xx/ADE71xx Preliminary Technical Data Rev. PrE | Page 64 of 148 ∫ = dt t Power Apparent Energy Apparent ) ( (30) The ADE75XX/ADE71XX achieves the integration of the apparent power signal by continuously accumulating the apparent power signal in an internal 48-bit register. The apparent energy register (VAHR[23:0]) represents the upper 24 bits of this internal register. This discrete time accumulation or summation is equivalent to integration in continuous time. Equation 31 expresses the relationship ⎪⎭ ⎪ ⎬ ⎫ ⎪⎩ ⎪ ⎨ ⎧ × = ∑ ∞ = → 0 0 ) ( n T T nT Power Apparent Lim Energy Apparent (31) where: n is the discrete time sample number. T is the sample period. The discrete time sample period (T) for the accumulation register in the ADE75XX/ADE71XX is 1.22 μs (5/MCLK). Figure 50 shows this discrete time integration or accumulation. The apparent power signal is continuously added to the internal register. This addition is a signed addition even if the apparent energy remains theoretically always positive. The 49 bits of the internal register are divided by VADIV. If the value in the VADIV register is 0, then the internal apparent energy register is divided by 1. VADIV is an 8-bit unsigned register. The upper 24 bits are then written in the 24-bit apparent energy register (VAHR[23:0]). RVAHR register (24 bits long) is provided to read the apparent energy. This register is reset to 0 after a read operation. VADIV APPARENT POWER + + VAHR[23:0] APPARENT POWER ARE ACCUMULATED (INTEGRATED) IN THE APPARENT ENERGY REGISTER 23 0 48 0 48 0 % TIME (nT) T APPARENT POWER SIGNAL = P Figure 50. ADE75XX/ADE71XX Apparent Energy Calculation Note that the apparent energy register is unsigned. By setting the VAEHF and VAEOF bits in the Interrupt Enable Register 2 SFR (MIRQENM, 0xDA), the ADE75XX/ADE71XX can be con- figured to issue an ADE interrupt to the 8052 core when the apparent energy register is half full or when an overflow occurs. The half full interrupt for the unsigned apparent energy register is based on 24 bits as opposed to 23 bits for the signed active energy register. Integration Times under Steady Load As mentioned in the last section, the discrete time sample period (T) for the accumulation register is 1.22 μs (5/MCLK). With full-scale sinusoidal signals on the analog inputs and the VAGAIN register set to 0x000, the average word value from apparent power stage is 0x1A36E2—see the section. The maximum value that can be stored in the apparent energy register before it overflows is 224 or 0xFF,FFFF. The average word value is added to the internal register, which can store 248 or 0xFFFF,FFFF,FFFF before it overflows. Therefore, the integration time under these conditions with VADIV = 0 is calculated as follows: Time = 055 xD 0 FFFF FFFF, xFFFF, 0 × 1.22 μs = 199 s = 3.33 min (32) When VADIV is set to a value different from 0, the integration time varies, as shown in Equation 33. Time = TimeWDIV = 0 × VADIV (33) Apparent energy Pulse output ADE75XX/ADE71XX also provides all the circuitry to have a pulse output those frequency is proportional to apparent power – see Energy-to-Frequency Conversion section. This pulse frequency output uses the calibrated signal after VAGAIN. This output can also be used to output a pulse those frequency is proportional to Irms. The pulse output is active low and should be preferably connected to an LED as shown on Figure 53. Line Apparent Energy Accumulation The ADE75XX/ADE71XX is designed with a special apparent energy accumulation mode, which simplifies the calibration process. By using the on-chip zero-crossing detection, the ADE75XX/ADE71XX accumulates the apparent power signal in the LVAHR register for an integral number of half cycles, as shown in Figure 51. The line apparent energy accumulation mode is always active. The number of half line cycles is specified in the LINCYC register, which is an unsigned 16-bit register. The ADE75XX/ADE71XX can accumulate apparent power for up to 65535 combined half cycles. Because the apparent power is integrated on the same integral number of line cycles as the line |
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