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ST10F271 数据表(PDF) 140 Page - STMicroelectronics

部件名 ST10F271
功能描述  16-bit MCU with 128 Kbyte Flash memory and 12 Kbyte RAM
PDF  173 Pages
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制造商  STMICROELECTRONICS [STMicroelectronics]
网页  http://www.st.com
标志 STMICROELECTRONICS - STMicroelectronics

ST10F271 数据表(HTML) 140 Page - STMicroelectronics

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Electrical characteristics
ST10F271
140/173
1.
Supposing to design the filter with the pole exactly at the maximum frequency of the
signal, the time constant of the filter is:
2.
Using the relation between CF and CS and taking some margin (4000 instead of 2048),
it is possible to define CF:
3.
As a consequence of step 1 and 2, RC can be chosen:
4.
Considering the current injection limitation and supposing that the source can go up to
12V, the total series resistance can be defined as:
from which is now simple to define the value of RL:
5.
Now the three element of the external circuit RF, CF and RL are defined. Some
conditions discussed in the previous paragraphs have been used to size the
component, the other must now be verified. The relation which allow to minimize the
accuracy error introduced by the switched capacitance equivalent resistance is in this
case:
So the error due to the voltage partitioning between the real resistive path and CS is
less then half a count (considering the worst case when VA = 5V):
The other conditions to be verified is the time constants of the transients are really and
significantly shorter than the sampling period duration TS:
For complete set of parameters characterizing the ST10F271 A/D Converter equivalent
circuit, refer to Section 24.7: A/D converter characteristics on page 131.
R
C
C
F
1
2
πf
0
------------
15.9
µs
=
=
C
F
4000 C
S
16nF
=
=
R
F
1
2
πf
0
C
F
---------------------
995
Ω 1kΩ
=
=
R
S
R
F
R
L
V
AM
I
INJ
-------------
4k
=
=
++
R
L
V
AM
I
INJ
-------------
R
F
R
S
2.9k
=
=
R
EQ
1
f
C
C
S
---------------10M
=
=
V
A
R
S
R
F
R
L
R
SW
R
AD
++
+
+
R
EQ
---------------------------------------------------------------------------
2.35mV
=
1
2
---LSB
<
τ
1
R
SW
R
AD
+
()
=
C
S
2.8ns
=
<< T
S = 1µs
10
τ
2
10 R
L
=
C
S
C
P1
C
P2
++
() 290ns
=
< T
S = 1µs



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