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AT89C51CC02CA-RATUM 数据表(PDF) 85 Page - ATMEL Corporation |
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AT89C51CC02CA-RATUM 数据表(HTML) 85 Page - ATMEL Corporation |
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85 / 156 page ![]() 85 AT/T89C51CC02 4126J–CAN–05/06 Figure 41. General Structure of a bit Period example of bit timing determination for CAN baudrate of 500 kbit/s: F OSC = 12 MHz in X1 mode => FCAN = 6MHz Verify that the CAN baud rate you want is an integer division of FCAN clock. FCAN/CANbaudrate = 6 MHz/500 kHz = 12 The time quanta TQ must be comprised between 8 and 25: TQ = 12 and BRP = 0 Define the various timing parameters: Tbit = Tsyns + Tprs + Tphs1 + Tphs2 = 12TQ Tsyns = 1TQ and Tsjw =1TQ => SJW = 0 If we chose a sample point at 66.6% => Tphs2 = 4TQ => PHS2 = 3 Tbit = 12 = 4 + 1 + Tphs1 + Tprs, let us choose Tprs = 3 Tphs1 = 4 PHS1 = 3 and PRS = 2 BRP = 0 so CANBT1 = 00h SJW = 0 and PRS = 2 so CANBT2 = 04h PHS2 = 3 and PHS1 = 3 so CANBT3 = 36h bit Rate Prescaler Oscillator 1/ Fcan Tscl System Clock One Nominal bit Tsyns (*) Tprs Sample Point (*) Synchronization Segment: SYNS Tbit Tsyns = 1xTscl (fixed) Data Tbit Tsyns Tprs Tphs1 Tphs2 ++ + = Tbit calculation: Transmission Point Tphs1 + Tsjw (3) Tphs2 - Tsjw (4) (1) Phase error ≤ 0 (2) Phase error ≥ 0 (3) Phase error > 0 (4) Phase error < 0 Tphs2 (2) Tphs1 (1) |
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