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SSM3582ACPZ-R7 数据表(PDF) 15 Page - Analog Devices

部件名 SSM3582ACPZ-R7
功能描述  2×, 31.76 W, Digital Input, Filterless Stereo Class D Audio Amplifier
PDF  58 Pages
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制造商  AD [Analog Devices]
网页  http://www.analog.com
标志 AD - Analog Devices

SSM3582ACPZ-R7 数据表(HTML) 15 Page - Analog Devices

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Data Sheet
SSM3582A
Rev. A | Page 15 of 58
20
10
–180
FREQUENCY (Hz)
0
–10
–20
–30
–40
–50
–60
–70
–80
–90
–100
–110
–120
–130
–140
–150
–160
–170
NO SIGNAL
ANALOG GAIN = 12.6V peak
RL = 4Ω (LOW EMI)
Figure 13. Amplitude vs. Frequency, No Signal, Analog Gain = 12.6 V peak
20
10
–180
FREQUENCY (Hz)
0
–10
–20
–30
–40
–50
–60
–70
–80
–90
–100
–110
–120
–130
–140
–150
–160
–170
NO SIGNAL
ANALOG GAIN = 16V peak
RL = 4Ω (LOW EMI)
Figure 14. Amplitude vs. Frequency, No Signal, Analog Gain = 16 V peak
0.001
1.000
0.002
0.005
0.010
0.020
0.050
0.100
0.200
0.500
20
20k
50
100
200
500
FREQUENCY (Hz)
1k
2k
5k
10k
100mW
1W
RL = 4Ω
PVDD = 4.5V
Figure 15. THD + N vs. Frequency, RL = 4 Ω, PVDD = 4.5 V
0.001
1.000
0.002
0.005
0.010
0.020
0.050
0.100
0.200
0.500
20
20k
50
100
200
500
FREQUENCY (Hz)
1k
2k
5k
10k
RL = 4Ω
PVDD = 12V
5W
1W
100mW
Figure 16. THD + N vs. Frequency, RL = 4 Ω, PVDD = 12 V
0.001
1.000
0.002
0.005
0.010
0.020
0.050
0.100
0.200
0.500
20
20k
50
100
200
500
FREQUENCY (Hz)
1k
2k
5k
10k
RL = 4Ω
PVDD = 16V
10W
1W
100mW
Figure 17. THD + N vs. Frequency, RL = 4 Ω, PVDD = 16 V
0.001
1.000
0.002
0.005
0.010
0.020
0.050
0.100
0.200
0.500
20
20k
50
100
200
500
FREQUENCY (Hz)
1k
2k
5k
10k
RL = 8Ω
PVDD = 4.5V
100mW
500mW
Figure 18. THD + N vs. Frequency, RL = 8 Ω, PVDD = 4.5 V



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