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PCF8833U/2DA 数据表(PDF) 57 Page - NXP Semiconductors

部件名 PCF8833U/2DA
功能描述  STN RGB - 132 X 132 X 3 driver
PDF  112 Pages
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制造商  PHILIPS [NXP Semiconductors]
网页  http://www.nxp.com
标志 PHILIPS - NXP Semiconductors

PCF8833U/2DA 数据表(HTML) 57 Page - NXP Semiconductors

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2003 Feb 14
57
Philips Semiconductors
Objective specification
STN RGB - 132
× 132 × 3 driver
PCF8833
When the required bias system (a) is defined, the LCD
supply voltage for a display size N can be determined; see
equation (4).
(4)
The parameter P in equation (4) is the number of
simultaneous selected rows. For the maximum number of
rows of 132, P = 4 is chosen. When partial Display mode
is selected the P value is set to 1 internally.
The bias voltages needed in a MRA LCD driver depends
on the number of simultaneous selected rows (P). The
bias voltages of the PCF8833 are given for P = 4 and
P = 1; see Fig.32. In the PCF8833 the maximum column
voltage (GMAX) is always lower or equal to the row
voltage F.
V
LCD
2a
V
ON
×
N
Pa
2
N2a
++
()
---------------------------------------
×
=
handbook, full pagewidth
MGU941
VLCD2
V2H
V1H
VC
V1L
V2L
VSS
P = 4
F
−F
VC
Gmax
−Gmax
VLCD2
V2H
VC
V2L
VSS
P = 1
F
−F
VC
Gmax
−Gmax
Fig.32 Bias levels for a MRA system with P = 4 and P = 1.
The bias voltage levels are a function of the row voltage
F and a:
(5)
(6)
(7)
(8)
Depending on the value of p, the bias levels are set in the
ratio of:
p=1:
αR − 2R − 2R −αR
p=4:
αR − R − R − R − R −αR
Where the value of
α is in the range from 0 to 4.
The value of F is determined by (
α +2) × R and the value
of Gmax is determined by 2 × R.
The relationship between the ratio F/Gmax and α:
(9)
or:
(10)
The relation between a and
α for a given p is the following:
(11)
This leads to the following bias systems given in Table 70.
F
V
LCD
2
-------------
=
FG
max
F
G
max
a
×
p
-----------------------
=
F
G
max
--------------
a
p
---
=
F
G
max
--------------
a
p
---
α 2
+
() R
×
2R
×
-----------------------------
α 2
+
()
2
------------------
1
α
2
---
+
==
=
=
α
F
G
max
-------------
1

 2
×
=
a
α
2
---
1
+

 p
×
=
α
a
p
---
1

 2
×
=



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