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TNETX15AE 数据表(PDF) 40 Page - Texas Instruments

部件名 TNETX15AE
功能描述  ADDRESS-LOOKUP DEVICE
PDF  78 Pages
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制造商  TI [Texas Instruments]
网页  http://www.ti.com
标志 TI - Texas Instruments

TNETX15AE 数据表(HTML) 40 Page - Texas Instruments

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TNETX15AE
ADDRESS-LOOKUP DEVICE
SPWS041A – AUGUST 1997 – REVISED OCTOBER 1997
40
POST OFFICE BOX 655303
DALLAS, TEXAS 75265
PRINCIPLES OF OPERATION
lookup algorithm (continued)
Each pointer points to a table in the next level. The TNETX15AE uses N bits in the address as an offset to this
table and, if a valid pointer is found, decode proceeds to the next level. A null pointer indicates that the entry
was not found (in this case the search fails). The width of the memory word (W) must increase as the memory
gets deeper, such that 2N+W – 1
≥ memory size; the memory address of the next pointer is (contents of current
table entry):(next N bits to decode).
a graphical example of the lookup algorithm
This example uses the following method to look up the number 0xB2 (10.11.00.10b), two bits at a time (N = 2).
Graphically, this number is represented in Figure 6.
00
01
10
11
00
01
10
11
00
01
10
11
00
01
10
11
Figure 6. Example of Lookup-Number Algorithm (Matching 0xB2)
The first table at offset 0x10b points to the second level (see Figure 6). The pointer at the second level (offset
by the second set of bits (0x11b)) points to the third table. This process continues until the last two bits are
matched. Matching 0xB2, two bits at a time, uses four tables, with each containing four possible pointers. Not
all locations in the tables are used, which potentially can lead to unused memory. Now, add 0xB0 (10.11.00.00b)
to the table. Figure 7 illustrates the results.
00
01
10
11
00
01
10
11
00
01
10
11
00
01
10
11
Figure 7. Example of Lookup-Number Algorithm (Adding 0xB0)
0xB0 follows exactly the same thread as 0xB2 and the only difference between the two is in the last table. 0xB0
matches offset 00b while 0xB2 matches offset 10b. There are now two numbers being represented, but there
are still four tables allocated.



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