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ADE7758ARWRL 数据表(PDF) 30 Page - Analog Devices |
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ADE7758ARWRL 数据表(HTML) 30 Page - Analog Devices |
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30 / 68 page ![]() ADE7758 Rev. A | Page 30 of 68 Voltage RMS Gain Adjust The ADC gain in each phase of the voltage channel can be adjusted for the rms calculation by using the voltage rms gain registers (AVRMSGAIN, BVRMSGAIN, and CVRMSGAIN). The gain of the voltage waveforms before LPF1 is adjusted by writing twos complement, 12-bit words to the voltage rms gain registers. The expression below shows how the gain adjustment is related to the contents of the voltage gain register. ⎟ ⎠ ⎞ ⎜ ⎝ ⎛ + × = 12 2 VRMSGAIN Gain without Values RMS Nominal Register VRMS of Content 1 For example, when 0x7FF is written to the voltage gain register, the ADC output is scaled up by 50%. 0x7FF = 2047d, 2047/212 = 0.5 Similarly, 0x800 = –2047d (signed twos complement) and the ADC output is scaled by –50%. ACTIVE POWER CALCULATION Electrical power is defined as the rate of energy flow from source to load. It is given by the product of the voltage and current waveforms. The resulting waveform is called the instantaneous power signal and it is equal to the rate of energy flow at every instant of time. The unit of power is the watt or joules/sec. Equation 5 gives an expression for the instantaneous power signal in an ac system. () ( t VRMS t v ω × × = sin 2 ) (3) () ( )t IRMS 2 t i ω × × = sin (4) where VRMS = rms voltage, IRMS = rms current. ( ) ( ) ( ) t i t v t p × = t) (2 VRMS IRMS – VRMS MS R I (t) p ω × × × = cos (5) The average power over an integral number of line cycles (n) is given by the expression in Equation 6. () IRMS VRMS dt t p nT 1 p nT 0 × = = ∫ (6) where t is the line cycle period. P is referred to as the active or real power. Note that the active power is equal to the dc component of the instantaneous power signal p(t) in Equation 5, that is, VRMS × IRMS. This is the relationship used to calculate the active power in the ADE7758 for each phase. The instantaneous power signal p(t) is generated by multiplying the current and voltage signals in each phase. The dc component of the instantaneous power signal in each phase (A, B, and C) is then extracted by LPF2 (the low-pass filter) to obtain the average active power information on each phase. Figure 64 shows this process. The active power of each phase accumulates in the corresponding 16-bit watt-hour register (AWATTHR, BWATTHR, or CWATTHR). The input to each active energy register can be changed depending on the accumulation mode setting (see Table 17). INSTANTANEOUS POWER SIGNAL p(t) = VRMS × IRMS – VRMS × IRMS × cos(2ωt) ACTIVE REAL POWER SIGNAL = VRMS × IRMS 0x19999A VRMS × IRMS 0xCCCCD 0x00000 CURRENT i(t) = 2 × IRMS × sin(ωt) VOLTAGE v(t) = 2 × VRMS × sin(ωt) Figure 64. Active Power Calculation Because LPF2 does not have an ideal “brick wall” frequency response (Figure 65), the active power signal has some ripple due to the instantaneous power signal. This ripple is sinusoidal and has a frequency equal to twice the line frequency. Because the ripple is sinusoidal in nature, it is removed when the active power signal is integrated over time to calculate the energy. 0 –4 –8 –12 –16 –20 –24 13 10 8 FREQUENCY (Hz) 30 100 Figure 65. Frequency Response of the LPF Used to Filter Instantaneous Power in Each Phase |
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