| 数据搜索系统,热门电子元器件搜索 |
|
ADP5014ACPZ-R7 数据表(PDF) 27 Page - Analog Devices |
|
|
|||||||||||||||||||||||||||||
ADP5014ACPZ-R7 数据表(HTML) 27 Page - Analog Devices |
|
27 / 34 page ![]() Data Sheet ADP5014 Rev. A | Page 27 of 34 DESIGN EXAMPLES This section provides an example of the step by step design procedures and the external components required for Channel 1. Table 12 lists the design requirements for this example. Table 12. Example Design Requirements for Channel 1 Parameter Specification Input Voltage VPVIN1 = 5 V ± 5% Output Voltage VOUT1 = 1.2 V Output Current IOUT1 = 4 A Output Ripple ΔVOUT1_RIPPLE = 5 mV in CCM mode Load Transient ±5%, at 20% to 80% load transient, 1 A/µs Although this example shows step by step design procedures for Channel 1, the procedures apply to all other buck regulator channels (Channel 2 to Channel 4). SETTING THE SWITCHING FREQUENCY The first step when setting the switching frequency is to determine the switching frequency for the ADP5014 design. In general, higher switching frequencies produce a smaller solution size due to the lower component values required, whereas lower switching frequencies result in higher conversion efficiency due to lower switching losses. The switching frequency of the ADP5014 can be set to a value from 500 kHz to 2.5 MHz by connecting a resistor from the RT pin to ground. The selected resistor allows users to make decisions based on the trade-off between efficiency and solution size. For more information, see the Oscillator section. However, the highest supported switching frequency must be assessed by checking the voltage conversion limitations enforced by the minimum on time and the minimum off time (see the Voltage Conversion Limitations section). In this design example, a switching frequency of 1.2 MHz achieves a good combination of small solution size and high conversion efficiency. To set the switching frequency to 1.2 MHz, use the following equation to calculate the resistor value, RRT: RRT (kΩ) = (100,000/fSW (kHz)) According to this equation, select standard resistor RRT = 82.5 kΩ. SETTING THE OUTPUT VOLTAGE Because the desired output voltage setting is less than VREF voltage, use the resistor divider from the accurate internal VREF reference voltage to set the desired output voltage and directly tie the feedback pin (FB1) to the output (see Figure 38). Select a 10 kΩ bottom resistor (R2) and then calculate the top resistor using the following equation: R1 = R2 × ((VREF − VOUT)/VOUT) where: VOUT is the output voltage. VREF is 2.0 V for Channel 1 to Channel 4. To set the output voltage to 1.2 V, choose the following resistor values: R1 = 6.65 kΩ, and R2 = 10 kΩ. SETTING THE CONFIGUATIONS (CFG1 AND CFG2) The CFG1 pin can be used to program the load output capability and parallel operation for all channels. For this example, choose RCFG1 = 0 kΩ. For more information, see the configuration in Function Configurations (CFG1 and CFG2). The CFG2 pin can be used to program the operation mode (FPWM or PWM/PSM mode), the enable mode (manual mode or sequence mode), the timer (×1 or ×8), and GPIO functionalities (PWRGD, SYNC-IN, CLK-OUT, UVO) for all channels. For this example, choose RCFG2 = 0 kΩ. For more information, see the configuration in Function Configurations (CFG1 and CFG2). SELECTING THE INDUCTOR The peak-to-peak inductor ripple current, ΔIL, is set to 30% of the maximum output current. Use the following equation to estimate the value of the inductor (L): SW L OUT IN f I D V V L × ∆ × − = ) ( where: VIN = 5 V. VOUT = 1.2 V. D is the duty cycle (D = VOUT/VIN = 0.24). ΔIL = 30% × 4 A = 1.2 A. fSW = 1.2 MHz. The resulting value for L is 0.63 µH. The closest standard inductor value is 0.8 µH; therefore, the inductor ripple current, ΔIL1, is 0.95 A. The inductor peak current is calculated using the following equation: IPEAK = IOUT + (ΔIL/2) The calculated peak current for the inductor is 4.48 A. The rms current of the inductor can be calculated using the following equation: 12 2 2 L OUT RMS I I I ∆ + = The rms current of the inductor is approximately 4.01 A. Therefore, an inductor with a minimum rms current rating of 4.01 A and a minimum saturation current rating of 4.48 A is required. However, to prevent the inductor from reaching its saturation point in current-limit conditions, it is recommended that the inductor saturation current be higher than the maximum peak current limit, typically 6 A, for reliable operation. Based on these requirements and recommendations, the COILCRAFT XAL5030-801MEB, with a direct current resistance (DCR) of 5.14 mΩ, is selected for this design. |
|
链接网址 |
| ALLDATASHEET是否为您带来帮助? [ DONATE ] |
关于 Alldatasheet | 广告服务 | 联系我们 | 隐私政策 | 数据表链接 | 链接交换 | 制造商名单 All Rights Reserved©Alldatasheet.com |
| Russian : Alldatasheetru.com | Korean : Alldatasheet.co.kr | Spanish : Alldatasheet.es | French : Alldatasheet.fr | Italian : Alldatasheetit.com Portuguese : Alldatasheetpt.com | Polish : Alldatasheet.pl | Vietnamese : Alldatasheet.vn Indian : Alldatasheet.in | Mexican : Alldatasheet.com.mx | British : Alldatasheet.co.uk | New Zealand : Alldatasheet.co.nz |
|
Family Site : ic2ic.com |
icmetro.com |