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AD9739-R2-EBZ 数据表(PDF) 43 Page - Analog Devices |
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AD9739-R2-EBZ 数据表(HTML) 43 Page - Analog Devices |
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43 / 50 page ![]() Data Sheet AD9739 Rev. E | Page 43 of 50 Figure 63 shows the IOUTP vs. DACCODE transfer function when I OUTFS is set to 19.65 mA. 20 18 10 12 14 16 8 6 4 2 0 0 4096 8192 12,288 DAC CODE 16,384 Figure 63. Gain Curve for FSC[9:0] = 512, DAC Offset = 1.228 mA Peak DAC Output Power Capability The maximum peak power capability of a differential current output DAC is dependent on its peak differential ac current, I PEAK, and the equivalent load resistance it sees. Because the AD9739 includes a differential 70 Ω resistance, it is best to use a doubly terminated external output network similar to what is shown in Figure 64. In this case, the equivalent load seen by the ac current source of the DAC is 25 Ω. If the AD9739 is programmed for I OUTFS = 20 mA, its peak ac current is 9.375 mA and its peak power delivered to the equivalent load is 2.2 mW (that is, P = I 2R). Because the source and load resistance seen by the 1:1 balun are equal, this power is shared equally; therefore, the output load receives 1.1 mW or 0.4 dBm. To calculate the rms power delivered to the load, the following must be considered: • Peak-to-rms of the digital waveform • Any digital backoff from digital full scale • The DAC’s sinc response and nonideal losses in external network For example, a reconstructed sine wave with no digital backoff ideally measures −2.6 dBm because it has a peak-to-rms ratio of 3 dB. If a typical balun loss of 0.4 dBm is included, −3 dBm of actual power can be expected in the region where the sinc response of the DAC has negligible influence. Increasing the output power is best accomplished by increasing I OUTFS, although any degradation in linearity performance must be considered acceptable for the target application. IPEAK = 15/32 × IOUTFS AC 70Ω IOUTFS = 8.6 – 31.2mA 180Ω RLOAD = 50Ω RSOURCE = 50Ω LOSSLESS BALUN 1:1 Figure 64. Equivalent Circuit for Determining Maximum Peak Power to a 50 Ω Load |
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