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AD6652BBC 数据表(PDF) 45 Page - Analog Devices |
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AD6652BBC 数据表(HTML) 45 Page - Analog Devices |
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45 / 76 page ![]() AD6652 Rev. 0 | Page 45 of 76 ST (BIST) self- hich is intended to test the integrity of the high speed ain s feature provides a simple pass/fail test, which gives el RAM is operational. Follow these est: t at , the 3-Bi Data MEM USER-CONFIGURABLE BUILT-IN SELF-TE The AD6652 includes two built-in test features to test the integrity of each channel. The first is a RAM BIST (built-in test), w random access memory within the AD6652. The second is channel BIST, which is designed to test the integrity of the m signal paths of the AD6652. The BIST functions are independ- ent of each other and can be operated simultaneously. RAM BIST Use the RAM BIST to validate functionality of the on-chip RAM. Thi confidence that the chann steps to perform this t 1. Put the channels to be tested into sleep mode via the External Address Register 0x01. 2. Program the RAM BIST enable bit in the RCF Register 0xA8 of the channel address registers to logic high. Wai least 1600 clock cycles, then perform Step 3. 3. Read back Register 0xA8 (see Table 19). If Bit 0 is high test is not yet complete. If Bit 0 is low, the test is complete and Bits 1 and 2 indicate the condition of the internal RAM. If Bit 1 is high, then CMEM is bad. If Bit 2 is high, then DMEM is bad. Table 19. BIST Register 0xA8 t Data Coefficient MEM xx1 Test incomplete Test incomplete 000 PASS PASS 010 FAIL PASS 100 PASS FAIL 110 FAIL FAIL CHANNEL BIST The channel BIST is a thorough test of the selected AD6652 un to tly. nel 0 in sleep mode. 2. Configure the channels to be tested as required for the application. This might require setting the NCO parameters, the decimation rates, scalars, and RCF coefficients. 3. Program the start hold-off counter, 0x83, to a value of 1 in the channel address registers of the channels to be tested. 4. Program Channel Address Registers 0xA5 and 0xA6 to all 0s for the channels to be tested. 5. Enable the channel BIST located at 0xA7 by programming Bits 19–0 to the number of RCF outputs to observe. 6. For External Address Register 5:3–0, program the desired SYNC CH bits to logic high to select which channels will receive a start soft-sync signal. 7. External Address Register 5:4 should be programmed high to emit a one-shot soft sync pulse for the start function. 8. Reset External Address Register 5:6 to 0 to allow user- provided test vectors. The internal pseudorandom number generator can also be selected to generate a PN data input sequence by setting Bit 7 high. 9. For External Address Register 5, an internal negative full- scale sine wave is output at the NCO frequency, when Bit 6 is set to 1 and Bit 7 is cleared. 10. When the SOFT_SYNC control register is written with the above parameters, the selected channels become active with the programmed attributes. 11. If the user is providing external vectors, then the chip can be brought out of sleep mode by one of the other methods. 12. After a sufficient amount of time, the channel BIST Signature Registers 0xA5 and 0xA6 contain a numeric value that can be compared to the expected value for a known good AD6652 with the exact same configuration. If the values are the same, then there is a very low probability of an error in the channel. Note: To better visualize these instructions, see Figure 53, Sync Control Block Diagram; Table 22, the External Memory Map; and Table 24, the Channel Address Registers Memory Map. signal path. With this test mode enabled, it is possible to use externally supplied test vectors or an internal pseudonoise (PN) data generator. An error signature register in the RCF monitors the output data of the channel and is used to determine if the proper data exits the RCF. If errors are detected, then each internal block can be bypassed and another test can be r debug the fault. The I and Q paths are tested independen Follow these steps to perform this test: 1. Place the channel(s) to be programmed in sleep mode at External Address 3:3–0. Set the appropriate bits high. Example 3:0 = 1 places Chan |
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