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ADP5140WACCZ-R7 数据表(PDF) 55 Page - Analog Devices |
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ADP5140WACCZ-R7 数据表(HTML) 55 Page - Analog Devices |
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55 / 128 page ![]() Data Sheet ADP5140 Rev. 0 | Page 55 of 128 APPLICATIONS INFORMATION INPUT CAPACITOR SELECTION Higher value input capacitors help reduce the input voltage ripple and improve transient response. To minimize supply noise, place the input capacitors as close as possible to the PVINx pins. The voltage rating of the input capacitors must be greater than the maximum input voltage. Input Capacitor Selection for the Buck Regulators The input capacitors reduce the input voltage ripple caused by the switch current on the power input pins. The loop composed of the input capacitor, the high-side MOSFET, and the low-side MOSFET must be kept as small as possible. A ceramic capacitor with low ESR from 10 μF to 47 μF is recommended. Ensure that the rms current rating of the input capacitor is larger than the value calculated from the following equation: __ _ (1 ) CIN RMS BUCK OUT BUCK BUCK BUCK I I DD = × ×− where ICIN_RMS_BUCK is the rms current through the buck input capacitor. IOUT_BUCK is the output current of the buck. DBUCK is the duty cycle of buck regulator (DBUCK = VOUT_BUCK/VIN_BUCK). Input Capacitor Selection for the Boost Regulator Because the input current of the boost regulator is continuous, and the switch current on the power input pin is low, there are no strict constraints on the input capacitor for the boost regulator. A typical 10 μF ceramic capacitor with a voltage rating higher than the input voltage is recommended. Input Capacitor Selection for the LDO Regulators Connect at least a 1 μF ceramic capacitor with low ESR from PVINx pins to GND to reduce the circuit sensitivity to the PCB layout, especially when long input traces or high source impedance are encountered. If an output capacitance greater than 1 μF is required, increase the input capacitor to match the capacitance. INDUCTOR SELECTION The inductor value is determined by the operating frequency, input voltage, output voltage, and inductor ripple current. Using a small inductor value leads to a faster transient response but degrades efficiency because of a larger inductor ripple current. Using a large inductor value leads to smaller ripple current and better efficiency but results in a slower transient response. Inductor Selection for the Buck Regulators An inductor ranging from 0.33 µH to 1 µH is recommended for the best balance between transient and efficiency performance. The inductor ripple current, ΔIL_BUCK, is typically set to one- third of the maximum load current. Use the following equation to calculate the inductor value: __ _ () IN BUCK OUT BUCK BUCK BUCK L BUCK SW VV D L If −× = ∆× where: VIN_BUCK is the input voltage of buck regulator. VOUT_BUCK is the output voltage of buck regulator. ΔIL_BUCK is the inductor current ripple of buck regulator. fSW is the switching frequency. Use the following equation to calculate the peak inductor current: _ __ 2 L BUCK PEAK BUCK OUT BUCK I II ∆ = + where: IPEAK_BUCK is the peak inductor current of the buck. The saturation current of the inductor must be larger than the peak inductor current. For ferrite core inductors with a quick saturation characteristic, the saturation current rating of the inductor must be higher than the current-limit threshold of the buck regulator to prevent the inductor from reaching saturation. Use the following equation to calculate the rms current of the inductor (IRMS_BUCK ): IRMS_BUCK = 12 2 _ 2 _ BUCK L BUCK OUT I I ∆ + Shielded ferrite core materials are recommended for low core loss and low EMI. Inductor Selection for the Boost Regulator An inductor from 2.2 µH to 10 µH is recommended for optimal balance between transient and efficiency performance. The inductor ripple current, ΔIL_BOOST, is typically set to 1/3 of the average inductor current, IAVE_BOOST as follows: _ _ 1 OUT BOOST AVE BOOST BOOST I I D = − where: IOUT_BOOST is the output current of the boost regulator. DBOOST is the duty cycle of the boost regulator. __ _ OUT BOOST IN BOOST BOOST OUT BOOST VV D V − = Use the following equation to calculate the inductor value: _ _ IN BOOST BOOST BOOST L BOOST SW VD L If × = ∆× where: VIN_BOOST is the input voltage of boost regulator. As the boost ratio increases (higher duty cycle), the average inductor current increases dramatically. Ensure that the |
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