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ST52T301 数据表(PDF) 18 Page - STMicroelectronics |
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ST52T301 数据表(HTML) 18 Page - STMicroelectronics |
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18 / 100 page ![]() Example 1: IF Input1 IS NOT Mbf1 AND Input4 is Mbf12 OR Input3 IS Mbf8 THEN Crisp1 is codified by the following instructions LDN 1 1 calculates the NOT α value of Input1 with Mbf1 and stores the result in the data stack LDP 4 12 fixes the α value of Input4 with M12 and stores the result in the data stack FZAND adds the NOT α and α values obtained with the operations LDN1 1 and LDP 4 12 LDK stores the result of the operation FZAND in the data stack LDP 3 8 fixes the α value of Input3 with Mbf8 and stores the result in the data stack FZOR implements the operation OR between the results obtained with the operations LDK and LDP CON crisp1 multiplies the result of the last Ω operation with the crisp value Crisp1 Example 2, the priority of the operator is fixed by the brakets: IF (Input3 IS Mbf1 AND Input4 IS NOT Mbf15) OR (Input1 IS Mbf6 OR Input6IS NOT Mbf14) THEN Crisp2 LDP 3 1 fixes the α value of Input3 with Mbf1 and stores the result in the data stack LDN 4 15 calculates the NOT α value of Input4 with Mbf15 and stores the result in the data stack FZAND adds NOT α and α values obtained with the operations LDP 3 1 and LDN 4 15 SKM stores the result of the operation FZAND in the memory register M LDP 1 6 fixes the α value of Input1 with Mbf6 and stores the result in the data stack LDN 2 14 calculates the NOT α value of Input6 with Mbf14 and stores the result in the data stack FZOR implements the operation OR between the α and NOT α values obtained with the two previous operations (LDP 1 6 and LDN 2 14) LDK stores the result of the operation OR in the data stack LDM copies the value of the memory register M in the data stack FZOR implements the operation OR between the last two values stored in the data stack (LDK and LDM) CON crips2 multiplies the result of the last Ω operation with the crisp value Crip2 At the end of the fuzzy rules set a byte, to identify the output involved in the rules, and the STOP istruction must be inserted. When the STOP instruction is performed, the control of the algorithm goes back to the CU. 18/99 ST52T301/E301 |
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