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AD9544/PCBZ 数据表(PDF) 50 Page - Analog Devices |
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AD9544/PCBZ 数据表(HTML) 50 Page - Analog Devices |
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50 / 62 page ![]() AD9544 Data Sheet Rev. 0 | Page 50 of 62 Note that this formula ignores other contributors to phase error, including jitter, frequency offset, and propagation delay variation. If the user has a prior knowledge of the timing of an external event, such as the switching of the reference input clock source via an external mux, rather than using the phase transient step detector, a more robust solution is to invalidate the associated reference manually. To do so, force a reference fault condition via the appropriate operational controls bit field. Using this method imposes the least impact on the steady state operation of the device. The only steady state impact is that the validation timer of the associated reference must be set to a duration that is longer (with suitable margin) than the duration between the assertion of the force fault condition and the occurrence of the external event. SKEW ADJUSTMENT Skew adjustment allows the user to associate a fixed phase offset with a reference input, which, for example, is useful in applications with redundant global navigation satellite system (GNSS)/ global positioning system (GPS) reference sources. That is, a user may have two or more GNSS/GPS sources that have identical frequency but may exhibit a fixed time offset due to a mismatch between antenna cable lengths. To activate the skew adjustment feature, program the 24-bit signed Profile x phase skew bit field (where x is the profile number, Profile 0 to Profile 7). The default value is zero, which disables the skew adjustment feature. A nonzero value enables the skew adjustment feature and denotes the desired time skew in units of picoseconds per the following equation: Time Skew = Profile x Phase Skew × 10−12 As an example, determine the value of the Profile x phase skew bit field necessary for a time skew of −35 ns. Solving the previous equation for the Profile x phase skew yields Profile x Phase Skew = (−35 × 10−9)/10−12 = −35,000 = 0xFF7748 (hexadecimal) |
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